1233.18x^2+800x-800=0

Solution for 1233.18x^2+800x-800=0 equation:

1233.18x^2+800x-800=0

a = 1233.18; b = 800; c = -800;
Δ = b2-4ac
Δ = 8002-4·1233.18·(-800)
Δ = 4586176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4586176}=\sqrt{64*71659}=\sqrt{64}*\sqrt{71659}=8\sqrt{71659}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-8\sqrt{71659}}{2*1233.18}=\frac{-800-8\sqrt{71659}}{2466.36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+8\sqrt{71659}}{2*1233.18}=\frac{-800+8\sqrt{71659}}{2466.36}
$